4sin^2x+12=4

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Solution for 4sin^2x+12=4 equation: 


Simplifying
4sin2x + 12 = 4

Reorder the terms:
12 + 4in2sx = 4

Solving
12 + 4in2sx = 4

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 4in2sx = 4 + -12

Combine like terms: 12 + -12 = 0
0 + 4in2sx = 4 + -12
4in2sx = 4 + -12

Combine like terms: 4 + -12 = -8
4in2sx = -8

Divide each side by '4n2sx'.
i = -2n-2s-1x-1

Simplifying
i = -2n-2s-1x-1

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